x^2+25x-264=0

Solution for x^2+25x-264=0 equation:

x^2+25x-264=0

a = 1; b = 25; c = -264;
Δ = b2-4ac
Δ = 252-4·1·(-264)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-41}{2*1}=\frac{-66}{2}
=-33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+41}{2*1}=\frac{16}{2}
=8
$